1-(1-x)^2/3=-2

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Solution for 1-(1-x)^2/3=-2 equation: 


x in (-oo:+oo)

1-(((1-x)^2)/3) = -2 // + 2

1-(((1-x)^2)/3)+2 = 0

(-1*(1-x)^2)/3+1+2 = 0

(-1*(1-x)^2)/3+(1*3)/3+(2*3)/3 = 0

1*3-1*(1-x)^2+2*3 = 0

2*x-x^2+2+6 = 0

2*x-x^2+8 = 0

2*x-x^2+8 = 0

2*x-x^2+8 = 0

DELTA = 2^2-(-1*4*8)

DELTA = 36

DELTA > 0

x = (36^(1/2)-2)/(-1*2) or x = (-36^(1/2)-2)/(-1*2)

x = -2 or x = 4

(x+2)*(x-4) = 0

((x+2)*(x-4))/3 = 0

((x+2)*(x-4))/3 = 0 // * 3

(x+2)*(x-4) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -2, 4 }

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